Challenger App

No.1 PSC Learning App

1M+ Downloads

9x+3x90=09^x+3^x-90=0എങ്കിൽ x എത്ര ?

A3

B6

C4

D2

Answer:

D. 2

Read Explanation:

9x+3x90=09^x+3^x-90=0

32x+3x90=03^{2x}+3^x-90=0

32x+3x=903^{2x}+3^x=90

3x(32+1)=903^x(3^2+1)=90

3x×(9+1)=903^x\times(9+1)=90

3x=90/10=93^x = 90/10 = 9

3x=323^x=3^2

x=2x=2 

 

 


Related Questions:

271/3×81/3×161/4=?27^{1/3}\times8^{1/3}\times16^{1/4}=?

x-(1/x) = 8 ആയാൽ x³-(1/x³) ന്റെ വില എത്ര?
(4)^5 ÷ (4)^8 =?
image.png

What is to be added to 2362^{36} to get 2372^{37}?