Question

$\frac{168+(72\div9)3}{2(1+\frac{12}{4})}=?$

• A. 24
• B. 25
• C. 26
• D. 27

Answer 1

Answer:

A. 24

$\frac{168+(72\div9)3}{2(1+\frac{12}{4})}$

$=\frac{168+8\times3}{2(\frac{16}{4})}$

$=\frac{168+24}{8}$

$=\frac{192}{8}$

$=24$