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f(x,y)=xy2+3x+2y3+logxf(x,y) = xy^2+3x+2y^3+logx എങ്കിൽ fx=?f_x= ?

Ay2+1x+3y^2+ \frac{1}{x} + 3

B1x+3\frac{1}{x} + 3

C1x3\frac{1}{x} -3

Dy21x3y^2-\frac{1}{x} -3

Answer:

y2+1x+3y^2+ \frac{1}{x} + 3

Read Explanation:

f(x,y)=xy2+3x+2y3+logxf(x,y) = xy^2+3x+2y^3+logx

fx=y2+3+0+1x=y2+1x+3f_{x} = y^2 + 3 + 0 + \frac{1}{x} = y^2 + \frac{1}{x} + 3


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