Challenger App

No.1 PSC Learning App

1M+ Downloads

If x5+2x4+x+6x^5+2x^4+x+6is divided by g(x), and quotient is x2+5x+7x^2+5x+7, then the positive degree of g(x) is :

A2

B3

C4

D5

Answer:

B. 3

Read Explanation:

g(x)=x5+2x4+x+6x2+5x+7g(x)=\frac{x^5+2x^4+x+6}{x^2+5x+7}

To find the degree consider x5/x2x^5/x^2

x5x2=x52=x3\frac{x^5}{x^2}=x^{5-2}=x^3

Degree of g(x) =3


Related Questions:

p(x)=2x2+3x+7p(x) =2x^2+3x+7,q(x)=6x2+8x9q(x)=6x^2+8x-9Find p(x)+q(x)

Find the reminder when p(x)=4x4+6x3+6x+6p(x)=4x^4+6x^3+6x+6 is divided by x+2x+2

In a polynomial P(x) = 2x³ + 9x² + kx + 3, P(-2) = P(-3) . Find the value of k
The product of the roots of $x^2 - 7x + 12 = 0 is______________
image.png