Challenger App

No.1 PSC Learning App

1M+ Downloads

The following figure is a combination of two semi-circles and a rectangle. If the radius of the circle is 14 cm and the length of the rectangle is 15 cm, the perimeter of the shape is :

image.png

A126 cm

B118 cm

C104 cm

D132 cm

Answer:

B. 118 cm

Read Explanation:

Solution:

Given:

Radius of the semicircle = 14cm

Length of the rectangle = 15cm

Formula used:

Circumference of a circle = 2πr

Calculation:

image.png

According to the diagram,

Perimeter of the shape is Sum of the circumference of two semicircles and the two length of the rectangle

Two semicircle = Circle

Circumference of the circle with radius 14cm =2×227×14=2\times{\frac{22}{7}}\times{14}

= 88 cm ----(1)

Two length of the rectangle = 2 × 15

= 30 cm ----(2)

Perimeter of the shape = (1) + (2)

= 88 + 30

= 118 cm

Answer is 118 cm.


Related Questions:

40 മീറ്റർ നീളവും 30 മീറ്റർ വീതിയുമുള്ള ഒരു കുളത്തിന്റെ ചുറ്റളവ് എത്ര ?
ഒരു കോൺ 45° ആയ ഒരു മട്ടത്രികോണത്തിൻറെ ലംബവശത്തിൻ്റെ നീളം 8 cm ആയാൽ അതിൻ്റെ കർണ്ണത്തിന്റെ നീളം എത്ര? *
The curved surface area of a cylindrical pillar is 264 m2 and its volume is 924 m3. Find theratio of its diameter to its height ?

The diagonal of a square is 42cm4\sqrt{2}cm. The diagonal of anothersquare whose area is doublethat of the first square is :

ഒരു സമചതുരത്തിന്റെ വിസ്തീർണ്ണം 64 cm2 ആകുന്നു. എങ്കിൽ സമചതുരത്തിന്റെ ചുറ്റളവ് എത്ര ?