Question

• A. 1
• B. 4
• C. 5
• D. 3

Answer 1

Answer:

A. 1

$1+tan^2x=sec^2x$

$1+cot^2x=cosec^2x$

$\frac{1}{(cosec^2x)^2}+\frac{tan^2x}{(sec^2x)^2}+\frac{1}{sec^2x}$

$sin^4x+\frac{sin^2x \times cos^4x}{cos^2x}+cos^2x$

$sin^2x(sin^2x+cos^2x)+cos^2x$ ------------- $(sin^2x+cos^2x=1)$

$sin^2x\times 1+cos^2x$

$1$