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1 മുതൽ 11 വരെയുള്ള എണ്ണൽസംഖ്യകളുടെ ക്യൂബുകളുടെ ശരാശരി?

A380

B396

C386

D376

Answer:

B. 396

Read Explanation:

ആദ്യത്തെ 'n' എണ്ണൽ സംഖ്യകളുടെ ക്യൂബുകളുടെ തുക = [n(n+1) / 2]² n=11 =[11x12/2]^2 =4356 ശരാശരി=4356/11=396


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