A6
B34
C79
D90
Answer:
Related Questions:
The value of −48÷[4×(6−5+1)]÷24 -48 \div [4 \times (6 - 5 + 1)] \div 24−48÷[4×(6−5+1)]÷24:
14+14÷14×14−14\frac{1}{4}+\frac{1}{4}\div\frac{1}{4}\times\frac{1}{4}-\frac{1}{4}41+41÷41×41−41
