1.25×1.25-2×1.25×0.25+0.25×0.25

Challenger App

★

1M+ Downloads

Answer:

(a-b)^2=a^2-2ab+b^2 (1.25-0.25)^2=1^2=1

Related Questions:

If a and b are two positive real numbers such that a + b = 20 and ab = 4, then the value of a³ + b³ is:

If $2(a^2 + b^2) = (a + b)^2$ then,

If x + y + z = 10, $x^3 + y^3 + z^3 = 75$ and xyz = 15, then find the value of $x^2 + y^2 + z^2-xy-yz-zx$

If a- =1/a=3, then what is a³-1/a³ ?