Question

$22\frac{1}{6}+7\frac{1}{6}-3\frac{1}{6}=$

• A. $$26\frac{1}{6}$$
• B. $$22\frac{1}{6}$$
• C. $$28\frac{1}{6}$$
• D. $$29\frac{1}{6}$$

Answer 1

Answer:

$$26\frac{1}{6}$$

$22\frac{1}{6}+7\frac{1}{6}-3\frac{1}{6}$

$=22+7-3+\frac{1}{6}+\frac{1}{6}-\frac{1}{6}$

$=26+\frac{1}{6}$

$=26\frac{1}{6}$