Question

$(2^5\div2^8)^5\times2^{-5}=?$

• A. $$1/20$$
• B. $$2^{-20}$$
• C. $$20^2$$
• D. $$1/2$$

Answer 1

Answer:

$$2^{-20}$$

$(2^5\div2^8)^5\times2^{-5}$

$a^m \div a^n = a^{m-n}$

$(2^{5-8})^5\times2^{-5}$

$\left(a^m\right)^n = a^{m \times n}$

$(2^{-3})^5\times2^{-5}$

$a^m \times a^n = a^{m+n}$

$2^{-15-5}$

$2^{-20}$