22+32−8=2\sqrt{2} + 3\sqrt{2} - \sqrt{8} =22+32−8= A$2\sqrt{2}$B$3\sqrt{2}$C$4\sqrt{2}$D$\sqrt{2}$Answer: $3\sqrt{2}$ Read Explanation: 22+32−82\sqrt{2} + 3\sqrt{2} - \sqrt{8}22+32−8 എന്ന സമവാക്യത്തിന്റെ ലളിത രൂപം 323\sqrt{2}32 ആണ്.8\sqrt{8}8 ചെറുതാക്കുക: 8=4×2=4×2=22\sqrt{8} = \sqrt{4 \times 2} = \sqrt{4}\times\sqrt{2}= 2\sqrt{2}8=4×2=4×2=22വില നൽകുക:22+32−82\sqrt{2} + 3\sqrt{2} - \sqrt{8}22+32−8 = 22+32−222\sqrt{2} + 3\sqrt{2} - 2\sqrt{2}22+32−22=52−22=5\sqrt{2}-2\sqrt{2}=52−22=32=3\sqrt{2}=32 Read more in App