3C+2T=700−−−−−−(1)
5C+3T=1100−−−−−−(2)
Multiplying (1) by 3 and (2) by 2 we get
$9C+6T=2100$
$10C+6T=2200$
solving above equation we get,
9C−10C=2100−2200
C=100
sub 'C' value in (1) we get,
$2T=700-300$
$T=200$
cost of 1 chair and 2 table is,
=1×100+2×200
=500