$ 3 \frac12+2 \frac13-4 \frac16 = $

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$3 \frac12+2 \frac13-4 \frac16 =$

A $1\frac12$

B $2\frac16$

C $1\frac23$

Answer:

1\frac23

$3 \frac12+2 \frac13-4 \frac16$

= $\frac72 + \frac73 - \frac{25}6$

= $\frac{35}6 - \frac{25}6$

= $\frac{10}6 = 5/3$

= $1\frac23$

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