315÷213÷112=?3\frac15\div2\frac13\div1\frac12=?351÷231÷121=? A11/35B32/35C35/32D32/105Answer: B. 32/35 Read Explanation: 315÷213÷1123\frac15\div2\frac13\div1\frac12351÷231÷121=16/3÷7/3÷3/2=16/3\div7/3\div3/2=16/3÷7/3÷3/2=16/3×3/7×2/3=16/3\times3/7\times2/3=16/3×3/7×2/3=3235=\frac{32}{35}=3532 Read more in App