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432 + (23 × 13) + (100 ÷ 2) =

A581

B881

C671

D781

Answer:

D. 781

Read Explanation:

432 + 299 + 50 = 781


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56 x 8 / 8 - 9+ 4 =
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21 ÷ 3 - 1 + 6 × 4 ന്റെ വില എന്ത് ?

Find the value of

[(27×3)×(3÷3×(1915)4)][(27\times3)\times(3\div3\times \frac{(19-15)}{4})]

In a certain code language, 'TEDI' is coded as '11' and 'SUCBVO' is coded as '13'. How is 'YXJIAZL' coded in the given language?