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(4)^5 ÷ (4)^8 =?

A1/4

B4^13

C4^3

D1/(4)^3

Answer:

D. 1/(4)^3

Read Explanation:

(4)^5 ÷ (4)^8 =(4)^5-8 =4^-3 =1/(4)^3


Related Questions:

In a geometric progression, the 5th term is 16 times the first term. Find the 7th term if the first term is 2

23×43×(65)2(36)4×(16)3= \frac {2^3 \times 4^3 \times (6^5)^2} {(36)^4 \times (16)^3} =

(125)23×(625)14=5x(125)^{\frac{2}{3}}\times(625)^{\frac{-1}{4}}=5^x

x=?

 

12523×62514=? 125^ {\frac{2}{3}}\times 625^ {\frac{-1}{4}} =?

310×272=92×3n3^{10}\times27^{2}=9^{2}\times3^n  

$$ആയാൽ  n എത്ര ?