If 4^n = 1024, what is 4^(n

Challenger App

★

1M+ Downloads

4^n = 1024 ആയാൽ 4^(n - 3) എത്ര?

B16

C64

D256

Answer:

4^n =1024 = 4^5 4^n =4^5 n = 5 4^(n-3) = 4^(5-3) = 4^2 = 16

Related Questions:

$\frac{(123-2)^{1/2}(78+3)^{1/4}}{243^{(1/5)}}$

$2^3+2^3+2^3+2^3$ ന് തുല്യമായതേത്?