Given:
615 coins consist of one rupee, 50 paise and 25 paise coins.
Their values are in the ratio of 3 : 5 : 7.
Calculation:
Let number of coins of 1 rupee, 50 Paise and 25 Paise be M, N and P respectively
⇒ M + N + P = 615
Also,
⇒ 100M ∶ 50N ∶ 25P = 3 ∶ 5 ∶ 7
Let
⇒ M ∶ N ∶ P = K
Then,
⇒ M = 3K/100, N = 5K/50, P = 7K/25
According to question,
⇒ (3K/100) + (5K/50) + (7K/25) = 615
⇒ 3K + 10K + 28K = 61500
⇒ 41K = 61500
⇒ K = 1500
∴ Number of 50 Paise coins = 5K/50 = (1500 × 5)/50 = 150
Therefore the number of 50 paise coins is 150.
Shortcut Trick
Coins value = Rs. 1, Rs. 0.50(50 paise), Rs. 0.25 (25 paise)
Coins are required in a ratio = 1 : 2 : 4 ....(1) [For equal value]
Their values are in the ratio = 3 : 5 : 7 .....(2)
So
Number of coins = (1) × (2)
ratio of number of coins = 3 : 10 : 28
So
3x + 10x + 28x = 615
x = 15
So
50 paise coins = 10x = 15 × 10 = 150