(64)2/3+(4)5/2+(216)1/3=?(64)^{2/3}+(4)^{5/2}+(216)^{1/3}=?(64)2/3+(4)5/2+(216)1/3=? A25B48C54D68Answer: C. 54 Read Explanation: (64)2/3+(4)5/2+(216)1/3(64)^{2/3}+(4)^{5/2}+(216)^{1/3}(64)2/3+(4)5/2+(216)1/3 =(43)2/3+(22)5/2+(63)1/3=(4^3)^{2/3}+(2^2)^{5/2}+(6^3)^{1/3}=(43)2/3+(22)5/2+(63)1/3 =42+25+6=16+32+6=54=4^2+2^5+6=16+32+6=54=42+25+6=16+32+6=54 Read more in App
