Question

$(64)^{2/3}+(4)^{5/2}+(216)^{1/3}=?$

• A. 25
• B. 48
• C. 54
• D. 68

Answer 1

Answer:

C. 54

$(64)^{2/3}+(4)^{5/2}+(216)^{1/3}$

$=(4^3)^{2/3}+(2^2)^{5/2}+(6^3)^{1/3}$

$=4^2+2^5+6=16+32+6=54$