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Acosec θ + cot θ

Bcosec θ - cot θ

Csec θ - cot θ

Dsec θ + cot θ

Answer:

B. cosec θ - cot θ

Read Explanation:

cosec θ - cot θ


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In the given figure ABC=ABD,BC=BDthenCAB=\angle{ABC} = \angle{ABD}, BC = BD then \triangle{CAB} =\triangle___________

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