Question

In this question, a group of numbers/symbols is coded using letters as per the table given below and the conditions which follow. The correct combination of codes following the condition is your answer.

Conditions:

• (i) If the first element is a number and the last, a symbol, the codes for these two are to be interchanged.

• (ii) If the first element is an odd number and the last, an even number, the first and last elements are to be coded as $\emptyset$.

• (iii) If both second and third elements are perfect squares, the third element is to be coded as the code for the second element.

How will '6 < % 2 #' be coded?

• A. ØYCAØ
• B. MHVAY
• C. YHVAM
• D. YYVAM

Answer 1

Answer:

C. YHVAM

The correct code combination for '6 < % 2 #' is Y H V A M.

1. Find the Base Codes from the Table:

   • 6 $\rightarrow$ M

   • < $\rightarrow$ H

   • % $\rightarrow$ V

   • 2 $\rightarrow$ A

   • # $\rightarrow$ Y

   Base Code Sequence: M H V A Y

2. Check the Conditions:

   • Condition (i): The first element (6) is a number and the last element (#) is a symbol. This condition applies, so the codes for the first and last elements must be interchanged (M and Y swap places).

   • Condition (ii): The first element (6) is an even number, not an odd number. This condition does not apply.

   • Condition (iii): The second element (<) and third element (%) are symbols, not perfect square numbers. This condition does not apply.

3. Apply the Change:

   • Interchanging the first and last letters transforms M H V A Y into Y H V A M.