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Acosec θ + tan θ

Bcosec θ - tan θ

Csec θ + tan θ

Dsecθ - tan θ

Answer:

C. sec θ + tan θ

Read Explanation:

sec θ + tan θ

Related Questions:

Given, A and B are complementary angles, and sinA = 3, what is tanB?
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If sin2A−cos2A=14sin^2A-cos^2A=\frac{1}{4}, find the value of cos2Acos^2A.

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