Question

• A. 8 and 6
• B. 2 and 8
• C. 20 and 8
• D. 4 and 20

Answer 1

Answer:

C. 20 and 8

squaring both sides

$2x+9=(13-x)^2$

$2x+9=169-26x+x^2$

$x^2-28x+160=0$

Find two numbers that multiply to 160 and add to 28:$(x-20),(x-8)$

answer is 20&8