6×17÷37+(4524−23+76×27)=6\times\frac17\div\frac37+(\frac{45}{24}-\frac23+\frac76\times\frac27)=6×71÷73+(2445−32+67×72)= A85/24B85/84C25/84D25/24Answer: A. 85/24 Read Explanation: 6×17÷37+(4524−23+76×27)6\times\frac17\div\frac37+(\frac{45}{24}-\frac23+\frac76\times\frac27)6×71÷73+(2445−32+67×72)=6×17÷37+(4524−23+13)=6\times\frac17\div\frac37+(\frac{45}{24}-\frac23+\frac13)=6×71÷73+(2445−32+31)=6×17÷37+(4524−13)=6\times\frac17\div\frac37+(\frac{45}{24}-\frac13)=6×71÷73+(2445−31)=6×17÷37+3724=6\times\frac17\div\frac37+\frac{37}{24}=6×71÷73+2437=6×17×73+3724=6\times\frac17\times\frac73+\frac{37}{24}=6×71×37+2437=2+3724=2+\frac{37}{24}=2+2437=8524=\frac{85}{24}=2485 Read more in App