81−4÷729(2−x)=94x81^{-4}\div 729^{(2-x)}=9^{4x} 81−4÷729(2−x)=94x എങ്കിൽ x = A-12B-14C-16D-10Answer: B. -14 Read Explanation: 81−4÷729(2−x)=94x81^{-4}\div 729^{(2-x)}= 9 ^{4x} 81−4÷729(2−x)=94x(92)−4÷(93)(2−x)(9^2)^{-4} \div (9^3)^{(2-x)}(92)−4÷(93)(2−x)am÷an=am−na^m \div a^n = a ^{m-n}am÷an=am−n9−8÷93(2−x)=94x9^{-8} \div 9^{3(2-x)} = 9^{4x}9−8÷93(2−x)=94x−8−(3(2−x))=4x-8-(3(2-x))=4x−8−(3(2−x))=4x−8−(6−3x)=4x-8-(6-3x)=4x−8−(6−3x)=4x−8−6+3x=4x-8-6+3x=4x−8−6+3x=4x−14=x-14=x−14=x Read more in App