Question

The sum of three consecutive multiples of 9 is 2457, find the largest one.

• A. 999
• B. 819
• C. 828
• D. 990

Answer 1

Answer:

C. 828

the numbers are $9x,9x+9,9x+18$

sum of these number

$9x+9x+9+9x+18=2457$

$27x+27=2457$

$27x=2430$

$x=90$

numbers are $810,819,828$