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A bag contains Rs. 550 in the form of 50 p, 25 p and 20 p coins in the ratio 2 ∶ 3 ∶ 5. The difference between the amounts that are contributed by the 50 p and the 20 p coins is:

ARs. 30

BRs. 20

CRs. 10

DRs. 0

Answer:

D. Rs. 0

Read Explanation:

Given:

Total Rs. = Rs.550

Calculation:

Let the number of denominations of 50p = 2x

the number of denominations of 25p = 3x

the number of denominations of 20p = 5x

Total paisa =550×100=55000paise=550\times{100}=55000 paise

According to the question:

(50×2x)+(25×3x)+(20×5x)=55000⇒(50\times{2x})+(25\times{3x})+(20\times{5x})=55000

⇒ 100x + 75x + 100x = 55000

⇒ 275x = 55000

x=55000275=200⇒x=\frac{55000}{275}=200

Amount in (Rs.) of 50p = 100x = (100×200)(100\times{200}) = 20000 paise = Rs.200

Amount in (Rs.) of 20p = 100x = (100×200)(100\times{200}) = 20000 paise = Rs.200

Required difference = 200 - 200 = 0

∴ The correct answer is 0.

Required difference = 200 - 200 = 0

∴ The correct answer is 0.


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