Given:
Total Rs. = Rs.550
Calculation:
Let the number of denominations of 50p = 2x
the number of denominations of 25p = 3x
the number of denominations of 20p = 5x
Total paisa =550×100=55000paise
According to the question:
⇒(50×2x)+(25×3x)+(20×5x)=55000
⇒ 100x + 75x + 100x = 55000
⇒ 275x = 55000
⇒x=27555000=200
Amount in (Rs.) of 50p = 100x = (100×200) = 20000 paise = Rs.200
Amount in (Rs.) of 20p = 100x = (100×200) = 20000 paise = Rs.200
Required difference = 200 - 200 = 0
∴ The correct answer is 0.
Required difference = 200 - 200 = 0
∴ The correct answer is 0.