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A bar of length L and cross section A is subjected to axial forces P at ends. The energy stored in the bar will be.

AP2L2AE\frac{P^2L}{2AE}

BP2L32AE\frac{P^2L^3}{2AE}

CP2L22AE\frac{P^2L^2}{2AE}

DPL32AE\frac{PL^3}{2AE}

Answer:

P2L2AE\frac{P^2L}{2AE}

Read Explanation:

The energy stored in a bar of length L and cross section A subjected to axial forces P at ends is given by the formula $\frac{P^2L}{2AE}$ . This is the strain energy stored in the bar due to elastic deformation. For a given L, A, and E, the strain energy is proportional to $P^2$.


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