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A boy rows a boat against a stream flowing at 2 kmph for a distance of 9 km, and then turns round and rows back with the current. If the whole trip occupies 6 hours, find the boy’s rowing speed in still water.

A4 kmph

B3 kmph

C2 kmph

D5 kmph

Answer:

A. 4 kmph

Read Explanation:

Let the speed of rowing be X.

Speed of Stream is 2 kmph.

Then the equation formed is,

9X2+9X+2=6\frac{9}{X-2}+\frac{9}{X+2}=6

9(X+2)+9(X2)X222=6\frac{9(X+2)+9(X-2)}{X^2-2^2}=6

9X+18+9X18X24=6\frac{9X+18+9X-18}{X^2-4}=6

18X=16(X24)18X=16(X^2-4)

9X=8(X24)9X=8(X^2-4)

8X29X32=08X^2-9X-32=0

On solving, we get the value of X as 4.


Related Questions:

A boat moving upstream takes 8 hours 48 minutes to cover a distance while it takes 4 hours to return to the starting point, downstream. What is the ratio of the speed of boat in still water to that of water current?
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