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A bullet train covers a fixed distance in 30 minutes at an average speed of 240 km/h. Due to track maintenance, it neehttos://gscstudy.com/ diverted, increasing the distance by 20%. If the train needs to arrive at its destination on time (i.e., in 30 minutes), what should its new average speed be in km/h?

A280 km/h

B300 km/h

C288 km/h

D320 km/h

Answer:

C. 288 km/h

Read Explanation:

Ignore the typo in the question and focus on the data.

Original distance

Time = 30 minutes = 0.5 hours
Speed = 240 km/h

Distance=240×0.5=120 km\text{Distance} = 240 \times 0.5 = 120 \text{ km}

New distance (20% increase)

120×1.2=144 km120 \times 1.2 = 144 \text{ km}

Required new speed

Time remains 0.5 hours:

Speed=1440.5=288 km/h\text{Speed} = \frac{144}{0.5} = 288 \text{ km/h}

Final Answer:

288 km/h\boxed{288 \text{ km/h}}


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