Question:
A6 days
B12 days
C4days
D8 days
Answer:
work done by A for 3 days = 3/12=1/4 Remaining work = 1 - 1/4 = 3/4 work done by (A+B) for 1 day=(3/4)*(1/3)=1/4 work done by B for 1 day=(1/4)-(1/12)=2/12=1/6. B alone will complete the work in 6 days
Related Questions: