Find the mean in the following distribution:
x
3
4
5
6
7
8
9
10
f
2
∣a→=5∣,∣b→∣=6,a→.b→=−25|\overset{\rightarrow}{a}=5|, |\overset{\rightarrow}{b}|=6, \overset{\rightarrow}{a}.\overset{\rightarrow}{b}=-25 ∣a→=5∣,∣b→∣=6,a→.b→=−25 ആയാൽ ∣a→×b→∣=|\overset{\rightarrow}{a} \times \overset{\rightarrow}{b}|=∣a→×b→∣=
a→=βi+2j+2k,b→=2i+2j+βk\overset{\rightarrow}{a}=\beta i+2j +2k , \overset{\rightarrow}{b} = 2i + 2j + \beta k a→=βi+2j+2k,b→=2i+2j+βk എന്നീ സദിശങ്ങൾ ലംബങ്ങളായാൽ ∣a→+b→∣−∣a→−b→∣=|\overset{\rightarrow}{a}+\overset{\rightarrow}{b}|-|\overset{\rightarrow}{a}-\overset{\rightarrow}{b}|=∣a→+b→∣−∣a→−b→∣=
a→\overset{\rightarrow}{a}a→ ഒരു ഏകക സദിശമാണ് , x→</span><span>−a→.(x→+a→)=12\overset{\rightarrow}{x} </span><span>- \overset{\rightarrow}{a}.(\overset{\rightarrow}{x}+\overset{\rightarrow}{a})=12x→</span><span>−a→.(x→+a→)=12 ആയാൽ x→\overset{\rightarrow}{x}x→ ന്ടെ വലിപ്പം എത്ര?
