Question

A candidate scores 25% marks and fails by 68 marks, while another candidate, who scores 50% marks, gets 42 marks more than the minimum required marks to pass the examination. Find the maximum marks for the examination.

• A. 410
• B. 440
• C. 430
• D. 400

Answer 1

Answer:

B. 440

Let the maximum marks be (M)
Let the pass marks be (P)

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From the first candidate

• Scores 25% of (M)

• Fails by 68 marks

$0.25M + 68 = P \quad \text{(1)}$

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From the second candidate

• Scores 50% of (M)

• Gets 42 marks more than pass marks

$0.50M = P + 42 \quad \text{(2)}$

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Substitute (P) from (1) into (2)

$0.50M = (0.25M + 68) + 42$
$0.50M = 0.25M + 110$
$0.25M = 110$
$M = 440$