App Logo

No.1 PSC Learning App

1M+ Downloads
A cylindrical pipe of diameter 1.5 m and thickness 1.5 cm is subjected to internal fluid pressure of 1.2 N/mm². Determine the longitudinal stress developed in the pipe.

A45 N/mm²

B60 N/mm²

C15 N/mm²

D30 N/mm²

Answer:

D. 30 N/mm²

Read Explanation:

Given, P = 1.2 MPa, D = 1.5mm = 1500mm t = 1.5 cm 15 mm,

Hoop stress σh=PD2t=1.2×15002×15=60MPa\sigma_{h} =\frac {PD}{2t} = \frac{1.2 \times 1500}{2 \times 15} = 60MPa

longitudinal stress σl=Pd4t=1.2×15004×15=30MPa\sigma_l = \frac{Pd}{4t} = {1.2 \times 1500}{4 \times 15} = 30MPa


Related Questions:

For a rivetted thin cylindrical shell of internal diameter (d), thickness of shell wall (t) and internal pressure (P) with efficiency of longitudinal joint (μi); the hoop stress (σc) will be given by:
Water is flowing in a pipe of 200 cm diameter under a pressure head of 10000 cm. The thickness of the pipe wall is 0.75 cm. The tensile stress in the pipe wall in MPa is:
Which of the following is the formula for circumferential stress in a thin-walled cylinder? (Where d = diameter of shell and t = thickness of shell)
What is the maximum possible radius of a sphere of thickness 1 cm made of a metal with maximum allowable stress as 90 MPa that can hold an internal pressure of 15 MPa without failing ?
Which of the following is not a real-life application of thin-walled pressure vessels?