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A cylindrical pipe of diameter 1.5 m and thickness 1.5 cm is subjected to internal fluid pressure of 1.2 N/mm². Determine the longitudinal stress developed in the pipe.

A45 N/mm²

B60 N/mm²

C15 N/mm²

D30 N/mm²

Answer:

D. 30 N/mm²

Read Explanation:

Given, P = 1.2 MPa, D = 1.5mm = 1500mm t = 1.5 cm 15 mm,

Hoop stress σh=PD2t=1.2×15002×15=60MPa\sigma_{h} =\frac {PD}{2t} = \frac{1.2 \times 1500}{2 \times 15} = 60MPa

longitudinal stress σl=Pd4t=1.2×15004×15=30MPa\sigma_l = \frac{Pd}{4t} = {1.2 \times 1500}{4 \times 15} = 30MPa


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