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A cylindrical tank of height 10 m and radius 5 m has a small circular cut of 0.5 m radius on its top surface. What would be the total surface area of the tank?

A599∏/4 m²

B156∏ m²

C299∏/2 m²

D150∏ m²

Answer:

A. 599∏/4 m²

Read Explanation:

Let’s quickly verify it in a clean way.

A cylinder has:

  • Radius ( r = 5 ) m

  • Height ( h = 10 ) m

  • A circular hole of radius ( 0.5 ) m on the top

    Curved surface area

2πrh=2π×5×10=100π2\pi rh = 2\pi \times 5 \times 10 = 100\pi

Bottom surface area

Top surface area (with hole)

π(52−0.52)=π(25−0.25)=24.75π\pi(5^2 - 0.5^2) = \pi(25 - 0.25) = 24.75\pi

Total surface area

100π+25π+24.75π=149.75π100\pi + 25\pi + 24.75\pi = 149.75\pi

Convert:
149.75=5994149.75 = \frac{599}{4}

So,
599π4 m2\boxed{\frac{599\pi}{4}\ \text{m}^2}

Final Answer: 599π/4 m²


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