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A=0.125+0.7290.25−0.45+0.81−0.25+1220−68A = \frac{0.125 + 0.729}{0.25 - 0.45 + 0.81} - 0.25 + \frac{12}{20} - \frac{6}{8}
ആയാൽ, A-യുടെ വില എത്രയാണ്?

A1

B1.4

C0

D2

Answer:

A. 1

Read Explanation:

The value of A is 1.

1. Simplify the first fraction using an algebraic identity:
Notice that the first fraction is in the form of the algebraic cube identity a3+b3a2−ab+b2=a+b\frac{a^3 + b^3}{a^2 - ab + b^2} = a + b:

  • 0.125=(0.5)30.125 = (0.5)^3

  • 0.729=(0.9)30.729 = (0.9)^3

  • 0.25=(0.5)20.25 = (0.5)^2

  • 0.45=0.5×0.90.45 = 0.5 \times 0.9

  • 0.81=(0.9)20.81 = (0.9)^2

Applying the identity:
(0.5)3+(0.9)3(0.5)2−(0.5)(0.9)+(0.9)2=0.5+0.9=1.4\frac{(0.5)^3 + (0.9)^3}{(0.5)^2 - (0.5)(0.9) + (0.9)^2} = 0.5 + 0.9 = \mathbf{1.4}

2. Convert the remaining fractions into decimals:

  • 1220=35=0.6\frac{12}{20} = \frac{3}{5} = \mathbf{0.6}

  • 68=34=0.75\frac{6}{8} = \frac{3}{4} = \mathbf{0.75}

3. Substitute these values back into the expression for A:
A=1.4−0.25+0.6−0.75A = 1.4 - 0.25 + 0.6 - 0.75

4. Perform final addition and subtraction:

  • Group the positive numbers: 1.4+0.6=2.01.4 + 0.6 = 2.0

  • Group the negative numbers: −(0.25+0.75)=−1.0-(0.25 + 0.75) = -1.0

A=2.0−1.0=1A = 2.0 - 1.0 = \mathbf{1}


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