Question

A hollow iron cylinder of inner radius 15 cm its outer radius is 16 cm and height of the cylindr is 63cm how much iron is required to construct the hollow circular cylinder?

• A. 6138
• B. 7148
• C. 6200
• D. 1528

Answer 1

Answer:

A. 6138

External radius $=16cm$

Thickness = 1 cm

Internal radius = 15 cm.

Volume of the material $=\pi{h}{(R^2-r^2)}$

$=\frac{22}{7}\times{63}\times{(16^2-15^2)}$

$=\frac{22}{7}\times{21}\times{31}$

$=6138cm^3$