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ഒരു കോൺകേവ് ദർപ്പണത്തിനു മുമ്പിൽ 10 cm അകലെ പ്രകാശിക്കുന്ന വസ്തു വച്ചപ്പോൾ അതിൻ്റെ യഥാർഥ പ്രതിബിംബം ദർപ്പണത്തിൽ നിന്ന് 40 cm അകലെ രൂപപ്പെടുന്നു. ദർപ്പണത്തിൻ്റെ ഫോക്കസ് ദൂരം കണക്കാക്കുക.

A-8 cm

B+8 cm

C-4 cm

D+4 cm

Answer:

A. -8 cm

Read Explanation:

The mirror formula is:

1/f = 1/v + 1/u

where:

  • f = ഫോക്കൽ ദൂരം

  • v = പ്രതിബിംബത്തിലേക്കുള്ള ദൂരം

  • u = വസ്തുവിലേക്കുള്ള ദൂരം

Given:

  • u = -10 cm (Since the object is placed in front of the mirror)

  • v = -40 cm (Since the real image is formed in front of the mirror)

Substituting the values in the mirror formula:

1/f = 1/(-40) + 1/(-10)

1/f = -1/40 - 1/10

1/f = (-1 - 4)/40

1/f = -5/40

1/f = -1/8

Therefore, f = -8 cm

So, the correct answer is A) -8 cm.


Related Questions:

The eye ball of a person is small in size. The power of the eye lens is normal he is having the problem of:

Which among the following mirror(s) always forms virtual and erect image?

  1. (A) Convex mirror
  2. (B) Plane mirror
  3. (C) Concave mirror

    A spherical mirror forms an erect and diminished image. Identify the correct statements about the spherical mirror.

    1. (A) The mirror is concave.
    2. (B) The mirror forms a virtual image.
    3. (C) The mirror has positive focal length.

      A spherical mirror converges a beam of light, at a given point on the principal axis. Which of the following statement(s) about the mirror is are true?

      1. (a) The mirror used in concave
      2. (b) The mirror has positive focal length
      3. (c) The point of convergence is the principal focus of the mirror
        What is the distance of the principal focus F from the pole P of the spherical mirror called?