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A man goes downstream with a boat to some destination and returns upstream to his original place in 5 hours. If the speed of the boat in still water and the stream are 10 km/hr and 4 km/hr respectively, the distance of the destination from the starting place is

A16 km

B18 km

C21 km

D25 km

Answer:

B. 18 km

Read Explanation:

Let the distance of the destination from the starting point be x km.

Rate downstream= (10 + 4) kmph = 14 kmph

Rate upstream = (10 – 4) kmph = 6 kmph

According to the question,

x14+x6=5\frac{x}{14}+\frac{x}{6}=5

3x+7x42=5\frac{3x+7x}{42}=5

10x=5×4210x=5\times{42}

x=21kmx=21km


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