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A man rows to a place 60 km distant and come back in 35 hours. He finds that he can row 4 km with the stream in the same time as 3 km against the stream. Find the speed in still water and in stream:

A1.5, 2

B0.5, 2.5

C3.5, 0.5

D2, 2.5

Answer:

C. 3.5, 0.5

Read Explanation:

Explanation:

  If he moves 4 km downstream in x hours.

Downstream speed =4x=\frac{4}{x}

Upstream speed =3x=\frac{3}{x}

Then 60(4x)+60(3x)=35\frac{60}{(\frac{4}{x})} +\frac{60}{(\frac{3}{x})}=35

60[(3x+4x)12]=3560[\frac{(3x+4x)}{12}]=35

60×7x12=3560\times{\frac{7x}{12}}=35

5×7x=355\times{7x} = 35 ==> x=1km.

Then Downstream speed=4km/hr ,

Upstream speed=3km/hr

U =(4+3)2=72=3.5km/hr=\frac{(4+3)}{2}=\frac{7}{2}=3.5km/hr

V=(43)2=12=0.5km/hr\frac{(4-3)}{2}=\frac{1}{2}=0.5km/hr


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