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A man travelled at a speed of 20m/min for 100 min, and at a speed of 70m/min for 50 min. His average speed is

A35 m/min

B703m/min\frac{70}{3}m/min

C25 m/min

D1103m/min\frac{110}{3} m/min

Answer:

1103m/min\frac{110}{3} m/min

Read Explanation:

Speed S1 = 20 m/min

Time T1= 100min

S2=70 m/min

T2=50 min

Average speed = 20×100+70×50100+50\frac{20\times{100}+70\times{50}}{100+50}

=2000+3500150=\frac{2000+3500}{150}

=5500150=\frac{5500}{150}

=1103m/min=\frac{110}{3} m/min


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