A mother is twice as old as her son. If 20 years ago, the age of the mother was 10 times the age of the son, what is the present age of the mother?
A38 years
B40 years
C43 years
D45 years
Answer:
D. 45 years
Read Explanation:
age of son = X years
Age of mother would be =2X
20 years ago;
10 (X -20) = 2X - 20
10X - 200 = 2X - 20
10X - 2X= - 20 + 200
8X = 180
Age of mother = 180/8 * 2 = 45 years