Question

A mother is twice as old as her son. If 20 years ago, the age of the mother was 10 times the age of the son, what is the present age of the mother?

• A. 38 years
• B. 40 years
• C. 43 years
• D. 45 years

Answer 1

Answer:

D. 45 years

age of son = X years Age of mother would be =2X 20 years ago; 10 (X -20) = 2X - 20 10X - 200 = 2X - 20 10X - 2X= - 20 + 200 8X = 180 Age of mother = 180/8 * 2 = 45 years