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A mother is twice as old as her son. If 20 years ago, the age of the mother was 10 times the age of the son, what is the present age of the mother?

A38 years

B40 years

C43 years

D45 years

Answer:

D. 45 years

Read Explanation:

age of son = X years Age of mother would be =2X 20 years ago; 10 (X -20) = 2X - 20 10X - 200 = 2X - 20 10X - 2X= - 20 + 200 8X = 180 Age of mother = 180/8 * 2 = 45 years


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