Question

A person covers certain distance in 2 hours at a speed of 10 km/h and some more distance in 4 hours at a speed of 6 km/h. Find his average speed for the entire distance covered.

• A. $$8\frac13$$
• B. $$9\frac13$$
• C. $$7\frac13$$
• D. $$6\frac13$$

Answer 1

Answer:

$$7\frac13$$

1. Calculate the distance covered in the first part:

• Speed (s1) = 10 km/h

• Time (t1) = 2 hours

• Distance (d1) = s1 x t1 = 10 km/h x 2 hours = 20 km

2. Calculate the distance covered in the second part:

• Speed (s2) = 6 km/h

• Time (t2) = 4 hours

• Distance (d2) = s2 x t2 = 6 km/h x 4 hours = 24 km

3. Calculate the total distance covered:

• Total distance (D) = d1 + d2 = 20 km + 24 km = 44 km

4. Calculate the total time taken:

• Total time (T) = t1 + t2 = 2 hours + 4 hours = 6 hours

5. Calculate the average speed:

• Average speed = Total distance / Total time

• Average speed = 44 km / 6 hours = 44/6 km/h

6. Simplify the fraction:

• 44/6 can be simplified by dividing both the numerator and the denominator by their greatest common divisor, which is 2.

• 44 ÷ 2 = 22

• 6 ÷ 2 = 3

Therefore, the average speed for the entire distance covered is 22/3 km/h = $7\frac13$ km/h