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A policeman follows a thief, who is 150 metres ahead of him., and they run at the speed of 6 km/h and 5 km/h, respectively.What distance does the policeman cover to catch up with the thief?

A880 metres

B870 metres

C890 metres

D900 metres

Answer:

D. 900 metres

Read Explanation:

Let’s do it cleanly using fractions

Convert speeds into m/s

  • Policeman:
    6 km/h=6×10003600=53 m/s6 \text{ km/h} = \frac{6 \times 1000}{3600} = \frac{5}{3} \text{ m/s}

  • Thief:
    5 km/h=5×10003600=2518 m/s5 \text{ km/h} = \frac{5 \times 1000}{3600} = \frac{25}{18} \text{ m/s}

    Relative speed

532518=302518=518 m/s\frac{5}{3} - \frac{25}{18} = \frac{30 - 25}{18} = \frac{5}{18} \text{ m/s}

Time to catch

Time=1505/18=150×185=540 seconds\text{Time} = \frac{150}{5/18} = 150 \times \frac{18}{5} = 540 \text{ seconds}

Distance covered by policeman

53×540=900 m\frac{5}{3} \times 540 = 900 \text{ m}

Final Answer: 900 m


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