A sector of a circle having a radius of 10 cm and has a central angle of ⅚ radians. What is the area of the sector?A26.18 cm²B8.33 cm²C10.47 cm²D12.5 cm²Answer: A. 26.18 cm² Read Explanation: For a sector with radius (r) and central angle (\theta) in radians:Area of sector=12r2θ\text{Area of sector}=\frac{1}{2}r^2\thetaArea of sector=21r2θSubstitute (r=10) cm and (θ=π6):(\theta=\frac{\pi}{6}):(θ=6π):Area\text{Area}Area=12(10)2(π6)=\frac{1}{2}(10)^2\left(\frac{\pi}{6}\right)=21(10)2(6π)=100π12=\frac{100\pi}{12}=12100π=25π3=\frac{25\pi}{3}=325πArea≈25×3.14163\text{Area} \approx \frac{25 \times 3.1416}{3}Area≈325×3.1416≈26.18 cm2\approx 26.18 \text{ cm}^2≈26.18 cm2Answer:(25π3 cm2≈26.18 cm2). (\frac{25\pi}{3}\ \text{cm}^2 \approx 26.18\ \text{cm}^2).(325π cm2≈26.18 cm2). Read more in App