Question

A student scored 80/80 marks in term 1 and 75/90 marks in term 2. What will be his percentage of final score, if the weightage given to the terms is 40% and 60%, respectively. (correct to the nearest integer)

• A. 85%
• B. 90%
• C. 95%
• D. 70%

Answer 1

Answer:

B. 90%

Term 1 percentage = 80/80=100%

Term 2 percentage = 75/90=83.33%

apply weightage

final score

$=(100\times 0.4)+(83.33\times 0.6)$

$=40+50$

$=90$%