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A sum borrowed under compound interest doubles itself in 10 years. When will it become fourfold of itself at the same rate of interest?

A24 years

B18 years

C20 years

D40 years

Answer:

C. 20 years

Read Explanation:

Solution:

Given : 

A sum doubles itself in 10 years

Formula used

Amount=P(1+R100)nAmount = P(1+\frac{R}{100})^n


If In the compound interest condition, Principal (P) and rate of interest (R) are the same, then 

Time is proportional to the Amount (A) after adding compound interest.

T1/T2 = A1/A2

Calculation:

Let, Total time to fourfold of itself at the same rate of interest = T2 

T1 = 10 years    (given)

A1 = 2P    (Amount after 10 years)

T1/T2 = A1/A2

10/T2 = 2P/4P

T2 = 20 years

Total time to fourfold of itself at the same rate of interest = 20 years


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